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Prove that a^0=1
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Many people ask this and I can prove it
Look: a^0=(a^1)/(a^1) isn't it? a^1-1=a^0 yes so any number divided by it's self is 1 a^1=a^1 so a^1/a^1=1 Conclusion is that a^0=1
Wait did you just answer yourself's question?
By the way there's a prerequisite that a not equal 0
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