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Mathematics 17 Online
OpenStudy (alexandervonhumboldt2):

Prove that a^0=1

OpenStudy (alexandervonhumboldt2):

Many people ask this and I can prove it

OpenStudy (alexandervonhumboldt2):

Look: a^0=(a^1)/(a^1) isn't it? a^1-1=a^0 yes so any number divided by it's self is 1 a^1=a^1 so a^1/a^1=1 Conclusion is that a^0=1

OpenStudy (kc_kennylau):

Wait did you just answer yourself's question?

OpenStudy (kc_kennylau):

By the way there's a prerequisite that a not equal 0

OpenStudy (solomonzelman):

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