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3/a-6 - 1/a-2 =3
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first, subtract 1/a from 3/a
2/a-6-2=3 then combine -6 and -2 ------>2/a-8=3
add 8 to both sides 2/a-8+8=3+8=11
2/a=11 multiply both sides by a 2/a*a=11*a
2=11a
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divide both sides by 11 2/11=a or a=2/11
is there such answer in your choices?
Well, I believe the question means 3/(a-6) - 1/(a-2) = 3
Multiply both sides by (a-6)(a-2) to get 3(a-2)-(a-6)=3(a-6)(a-2)
Expand and simplify to get 3a^2-24a+36=2a
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Take the RHS to the LHS to get 3a^2-26a+36=0
Solve it by quadratic formula to get a = (13-sqrt(61))/3 or a = (13+sqrt(61))/3
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