Question

Find the standard form of the equation of the parabola with a focus at (5, 0) and a directrix at x = -5.

Answer 1

Equation of a parabola with focus \((p,0)\) and directrix \(x=-p\) will have the equation:\[
4px = y^2
\]

Answer 2

so, 4(5)(-5)=y^2 @wio

Answer 3

No, you only need to plug in \(p\), while \((x,y)\) remain as they are.

Answer 4

okay, so 4(5)x=y^2?
20x+y^2?
what now?
@wio

Answer 5

No \(+\). It is \(=\).

Answer 6

And you're done.

Answer 7

wow! thats simple! Thank you so much! @wio

Answer 8

It would be more complex if the vertex wasn't at \((0,0)\).