Question

trigonometry
3) Simplify.
a)sec x/tan x
b)(sec x – 1)(sec x + 1)

Answer 1

a) Write \(\sec x\) and \(\tan x\) in terms of \(\sin x\) and \(\cos x\)
b) multiply the two and look at the idenity \(\sin^2 x+\cos^2 x=1\)

Answer 2

\[\sec x=\frac{ 1 }{ \cos x }\]

Answer 3

so:
\[\frac{ \sec x }{ \tan x }=\frac{ 1/\cos x }{ \sin x/\cos x }=...\]

Answer 4

hint: first fraction times the inverse of the second fraction

Answer 5

\[\frac{ 1 }{ \cos x }\frac{ \cos x }{ \sin x }=....\]

Answer 6

the second one is fairly easy
just use (a-b)(a+b)=a^2-b^2

Answer 7

then use an identity another form of pythagorean identity

Answer 8

i still don't get it