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Only three whole numbers exist such that the digits from left to right are consecutive integers in increasing order and the number is divisible by 24. What are the three numbers?
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you don't have that many choices
Easy I know
321 432 543 654 765 876 987
oh i misread the qeustion it does not say "3 digit number" does it?
left to right, not right to left @Marki
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i read 3 digits :\
haha k , i'll try again
\[24\times 19=456\]
I'll check 123456789 for you. Ok, it's odd, not divisible by 24.
This seems like a project euler question...
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24=8*3 means sum of digits is divisible by 3 and last 3 digits divides 8
|dw:1419215331596:dw|
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