Question

Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).

y = -one thirdx - 6
y = -one thirdx - 14
y = 3x - 6
y = 3x - 14

Answer 1

@ganeshie8

Answer 2

@AnswerMyQuestions

Answer 3

First we have to find the slope of the equation given. The reason we do this is because a parallel line will have the same slope. Remember that in y = mx + b form, the number in the m position represents the slope. So we will put our equation in y = mx + b form.

3x - y = -3 --- subtract 3x from both sides
-y = -3x - 3 --- multiply by -1 to make y positive
y = 3x + 3
The number in the m position is 3, therefore, that is our slope.

Now we will use y = mx + b form again.
y = mx + b
we already know the slope(m) = 3
(4,-2).....x = 4 and y = -2
now we just need to find b, the y intercept
so lets sub
-2 = 3(4) + b
-2 = 12 + b
-2 - 12 = b
-14 = b

so our parallel equation is : y = 3x - 14