Question

If y = 4x – 1, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?
{(2, 5), (4, 12), (9, 25)}
{(–3, –10), (0, –2), (6, –18)}
{(7, 24), (–1, –9), (–8, 35)}
{(1, 3), (–2, –9), (0, –1)}d

Answer 1

It's asking which set of ordered pairs are true for y = 4x - 1.

Answer 2

yes ok

Answer 3

Let's try this set:

{(1, 3), (–2, –9), (0, –1)}

Now let's first plug in (1, 3).

y = 4x - 1

3 = 4(1) - 1

Simplify it, what do you get?

Answer 4

{(1, 3), (-2, -9), (0, -1)}

Answer 5

omg im lost

Answer 6

if you wanted to find if a point (6,2) is on the line y=4x-1 (for example)
you would do this:
2=4(6)-1
2=24-1
2=23

so (6,2) is NOT on the line y=4x-1.

If you wanted to find if a point (2,5) is on the line y=4x-1 (for example)
you would do this:
5=4(2)-1
5=6-1
5=5

so (2,5) is on the line y=4x-1.

Answer 7

pick first point of like (2,5).... then put the value of x (2) in the equation and see if gives 5 or not ....

Answer 8

see how I am plugging in my points?

Answer 9

yesss

Answer 10

ok so

Answer 11

so what answer do you pick?
(or you want we can do it in a different form, of an arithmetic sequence, if you like...)

Answer 12

im so confused lol

Answer 13

look, y=4x-1 ..right?
whatever the x is, we multiply it times 4 and subtract 1.
so.

when x=1, y=(1 * 4) - 1 ---> y=3
when x=2, y=(2 * 4) - 1 ---> y=8-1 ---> y=7
when x=3, y=(3 * 4) - 3 ---> y=12-1 ---> y=11

and on....

~~~~~~~~~~~~~~~~~~~
or you can look at it as:
when x =1, then y= 3,
and
when x=2, then y=7

So for each x, we add 4 for y.
so the terms would come along:

x = 1 2 3
y = 3 7 11

(when x=0, the y is: y=4(0)-1, y=-1 )
x = 0 -1 -2
y = -1 -5 -9

Answer 14

I think I am offering you enough assistance to solve this.