Hello I have homework and I'm really confused 52) |x+3|=-2
| x + 3 | = -2 (x + 3) = -2 x = -2 - 3 x = -5 -(x + 3) = -2 -x - 3 = -2 -x = -2 + 3 -x = 1 x = -1 so x = -5 and x = -1 http://www.purplemath.com/modules/solveabs.htm
I left a link that I think you should look at.
absolute value measures distance from an origin, so its never negative.
at least it has no real solutions
check out the link...there are negative values for x
we can graph |x+3| and -2, and try to see where they cross at: |dw:1419272441516:dw|
can you test out your solutions?
| x + 3 | = -2 | -5 + 3 | = -2 | -2} = -2 2 = -2 oh....I see what you mean
:) the confusion arises most likely from thinking that there has to be a solution ... when 'no real solutions' is a perfectly adequate way to define the solutions.
good explaining :)
Can you guys halo me with another question 4|k+5|>8
how far can you get on your own with it?
divide and then split the absolute into 2 cases if need be.
Sorry I don't understand what you just said.
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