Can someone help please? Graph the function in the interval form of 2 to 2pi. y= 2 cos (theta+ pi/6) +2.

Question

campbell_st · Answer

well the graph is centred on y = 2 has an amplitude 2 and a phase shift of pi/6 to the left.

campbell_st · Answer

then knowing this use a table of values to find some values to graph

anonymous · Answer

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anonymous · Answer

When we graph trig functions, the transformations of sine and cosines can involve graphing functions in the following format: $$y=a \times f(b(x-h \pi))+k$$ where a is the amplitude and k represents the vertical displacement, in your case, a = 2 and vertical displacement = 2 as well. Usually a good way to start off these problems is by drawing the graph of the function (y = cosx) and transforming it from there. So see what you can do with this, here is a graph of y = cosx
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