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Mathematics 13 Online
OpenStudy (anonymous):

Can someone help me answer these? http://gyazo.com/b1a1350bfe216d35ae04d528e0d4452c

OpenStudy (anonymous):

???

OpenStudy (anonymous):

\[y = \frac{ -3x }{ 4 } + 3\] \[y-3= \frac{ -3x }{ 4 }\] \[4(y-3)=-3x\] \[4y-12=-3x\] \[3x+4y=12\]

OpenStudy (anonymous):

?

OpenStudy (anonymous):

in what part are u confused?

OpenStudy (anonymous):

Is that for question 16?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Theres not "+" in the options though

OpenStudy (anonymous):

Did you mean division?

OpenStudy (anonymous):

that's addition right there in the image isn't it.

OpenStudy (anonymous):

nope i dont think so :P

OpenStudy (anonymous):

yep it is addition lol download the image and zoom it.. you'll see. :D

OpenStudy (anonymous):

O ok lol

OpenStudy (anonymous):

Can you do 17 and 18 please?

OpenStudy (anonymous):

okay but did u understand how to get the answer? :)

OpenStudy (anonymous):

To be honest, no. xD

OpenStudy (anonymous):

\[y=\frac{ -2x }{ 3 } + 2\] subtracting 2 to both sides (so 2 at the right will be canceled) \[y-2=\frac{ -2x }{ 3 }\] multiply 3 to both side (so 3 at the right will be canceled) \[3(y-2)=-2x\] \[3y-6=-2x\] now, standard form is --> x+y=z where z is constant ye? the final answer must be \[2x+3y=6\] make sense?

OpenStudy (anonymous):

Yeah helps. thanks

OpenStudy (anonymous):

i think you can do the last question ?

OpenStudy (anonymous):

no help me :p

OpenStudy (anonymous):

you try :) come on :P

OpenStudy (anonymous):

ok ill try

OpenStudy (anonymous):

i think i got it. Thank u for the help. I have more questions are u willing to help me ? :P

OpenStudy (anonymous):

http://gyazo.com/08ec7ddc0e503a6860803691efd808d0

OpenStudy (anonymous):

for the first one it is perpendicular because the slope of the first given equation is -4 while the other is 1/4 we can tell if two lines are parallel when we get -1 when we multiply their slopes :) \[(-4)\times\frac{ 1 }{ 4 } = -1\]

OpenStudy (anonymous):

for the second one the answer is neither

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