Can someone help me answer these? http://gyazo.com/b1a1350bfe216d35ae04d528e0d4452c
???
\[y = \frac{ -3x }{ 4 } + 3\] \[y-3= \frac{ -3x }{ 4 }\] \[4(y-3)=-3x\] \[4y-12=-3x\] \[3x+4y=12\]
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in what part are u confused?
Is that for question 16?
yes
Theres not "+" in the options though
Did you mean division?
that's addition right there in the image isn't it.
nope i dont think so :P
yep it is addition lol download the image and zoom it.. you'll see. :D
O ok lol
Can you do 17 and 18 please?
okay but did u understand how to get the answer? :)
To be honest, no. xD
\[y=\frac{ -2x }{ 3 } + 2\] subtracting 2 to both sides (so 2 at the right will be canceled) \[y-2=\frac{ -2x }{ 3 }\] multiply 3 to both side (so 3 at the right will be canceled) \[3(y-2)=-2x\] \[3y-6=-2x\] now, standard form is --> x+y=z where z is constant ye? the final answer must be \[2x+3y=6\] make sense?
Yeah helps. thanks
i think you can do the last question ?
no help me :p
you try :) come on :P
ok ill try
i think i got it. Thank u for the help. I have more questions are u willing to help me ? :P
for the first one it is perpendicular because the slope of the first given equation is -4 while the other is 1/4 we can tell if two lines are parallel when we get -1 when we multiply their slopes :) \[(-4)\times\frac{ 1 }{ 4 } = -1\]
for the second one the answer is neither
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