divide (y^2-3y+2)/(y^2+5y+6) / (y^2+2y-8)/(y^2+y-12)

use complete sentences to explain how to simplify this?

Question

divide (y^2-3y+2)/(y^2+5y+6) / (y^2+2y-8)/(y^2+y-12) 

use complete sentences to explain how to simplify this?

mathmath333 · Answer

$$\text{factor all of these, ex.}\y^2-3y+2\=y^2-y-2y+2\=y(y-1)-2(y-1)\=(y-1)(y-2)$$

danjs · Answer

I am assuming this is it

$$\frac{ y^2 - 3y +2 }{ y^2 + 5y +6 } *\frac{ y^2 + y -12 }{ y^2+2y - 8 }$$

danjs · Answer

$$\frac{ (y-2)(y-1) }{ (y+3)(y+2) }*\frac{ (y+4)(y-3) }{ (y+4)(y-2) }$$

danjs · Answer

Cancel out, (y+4) , (y-2) 

$$\frac{ (y-1)(y-3) }{ (y+3)(y+2) }$$

danjs · Answer

$$\frac{ y^2 - 4y + 3 }{ y^2 + 5y +6 }$$

danjs · Answer

1) multiply by the reciprical of the bottom fraction
2)Factor each polynomial 
3) cancel common terms, ratios of 1
4) distribute out the remaining terms, if you want to.

danjs · Answer

This was an old post, figure i would just complete it for you to review later.