Question

Factor completely 3a^4y^3 - 12a^3y^2 + 6a^2y.

A. 3(a^4y^3 - 4a^3y^2 + 2a^2y)
B. 3a^2y(a^2y^2 - 4ay + 2)
C. 3y(a^4y^2 - 4a^3y + 2a^2)
D. Prime

Answer 1

I think its B.

Answer 2

You got it! :D

Answer 3

take it step by step
GCF of 3 6 and 12 is so take 3 out

Answer 4

what about the terms in a?

Answer 5

For a, I got 2 and y is 1.

Answer 6

right

Answer 7

So I assumed it was B because it was the only one that fit, and when I distributed, I got the equation in the question.

Answer 8

\(3a^4y^3 - 12a^3y^2 + 6a^2y\)

The GCF is \(3a^2y\)..

That leaves you with:

\(a^2y^2 - 4ay + 2\)

Answer 9

yes B is correct

Answer 10

Thanks. ^-^

Answer 11

yw

Answer 12

So we put it as:

\(3a^2y(a^2y^2 - 4ay + 2)\)

Answer 13

yes