Two cars leave towns
750
kilometers apart at the same time and travel toward each other. One car's rate is
18
kilometers per hour more than the other's. If they meet in
5
hours, what is the rate of the faster car?
Do not do any rounding.

Question

Two cars leave towns 
750
 kilometers apart at the same time and travel toward each other. One car's rate is 
18
 kilometers per hour more than the other's. If they meet in 
5
 hours, what is the rate of the faster car?
Do not do any rounding.

anonymous · Answer

18x*5x=750

ganeshie8 · Answer

this is slightly different from previous problem
we need to be a lil bit careful here

ganeshie8 · Answer

see you're not given speeds of cars, you're given how much faster one car is compared to the other

ganeshie8 · Answer

say the speed of faster car is $x$
then the speed of slower car would be $x-18$

yes ?

anonymous · Answer

18 and 5

anonymous · Answer

yes?

ganeshie8 · Answer

and you know they travel exactly 750 kilometers by the time they meet (in 5 hours)

ganeshie8 · Answer

$$5x + 5(x-18) = 750$$

solve $x$

anonymous · Answer

5x+5x-90=750
10x-90=750
10x=840
x=84

ganeshie8 · Answer

yes thats the speed of faster car

anonymous · Answer

thanks i think thats it for know u are great talk to u later

ganeshie8 · Answer

you're welcome ! have good sleep :)