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Mathematics
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OpenStudy (natsent06):
WILL GIVE MEDAL
Subtract 2c^2 + 3c - 4 from 0.
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OpenStudy (sleepyjess):
So \(0-2c^2+3c-4\)?
OpenStudy (natsent06):
yep i think
OpenStudy (solomonzelman):
no
OpenStudy (natsent06):
not really
OpenStudy (solomonzelman):
"Subtract 2c^2 + 3c - 4 from 0" means \(\large\color{black}{ 0-(2c^2 + 3c - 4) }\)
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OpenStudy (sleepyjess):
Oh yes. ^
OpenStudy (natsent06):
A) -2c2 + 3c - 4
B) -2c2 - 3c + 4
C) -2c2 - 3c - 4
D) -2c2 + 3c + 4
OpenStudy (natsent06):
>?
OpenStudy (sleepyjess):
\(0-(2c^2+3c-4)\) means to multiply everything inside the parentheses by -1, then subtract it from 0.
OpenStudy (solomonzelman):
for example: \(\large\color{black}{ -(x^3+x-31)~~~\Longrightarrow ~~~-x^3-x+31}\)
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OpenStudy (solomonzelman):
do the same to yours: \(\large\color{black}{-(2c^2+3c-4)~~~~\Longrightarrow }\)
OpenStudy (natsent06):
so i think the answer is a
OpenStudy (natsent06):
does that sound correct?
OpenStudy (solomonzelman):
nope, it is not a.
OpenStudy (natsent06):
:/
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OpenStudy (natsent06):
i got -11
OpenStudy (natsent06):
?
OpenStudy (sleepyjess):
If you are multiplying by -1, you are basically going to change all of the signs. Negative becomes positive, and positive becomes negative.
OpenStudy (natsent06):
so b?
OpenStudy (solomonzelman):
yes
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OpenStudy (sleepyjess):
Yes
OpenStudy (natsent06):
cool thanks guys!
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