Question

log3 2x- 5 log3 y
A. log3 (2x- y^5)
B. log3 (2x-5y)
C. log3 2x/ 5y
D. log3 2x/y^5

Answer 1

lol i forgot how to do this

Answer 2

thats okay. me 2!

Answer 3

\[a * \log _{b}x = \log _{b} x ^{a}\]

Answer 4

and one more thing

Answer 5

so subtraction become what ??
opposite of last one hope you remember

Answer 6

\[\log(x) - \log(y) = \log \frac{ x }{ y }\]

Answer 7

hope these guys can help ya

Answer 8

Those are the 2 rules you need to use

Answer 9

+

Answer 10

nope
subtraction -----> division
addition ------> multiplication

Answer 11

\[\log _{3}(2x) - \log _{3}(y^5)\]

Answer 12

oh

Answer 13

that is the first step, only one left to do

Answer 14

this one is opposite to last one
last time was expand log
now this time condense

Answer 15

power become multiplication of log
so first change that 5 log3 y