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Mathematics 50 Online
OpenStudy (anonymous):

Verify the identity. Show your work cot θ ∙ sec θ = csc θ

OpenStudy (anonymous):

i did it this way: secx -1 / tanx (1/cosx -1)/ tanx (1/cosx - cosx/cosx)/(sinx/cosx) (1 - cosx / cosx) / (sinx/cosx) (1 - cosx) / sinx For the other side (right), Step B: (sinx/cosx) / (1/cosx +1) (sinx/cosx) / (1/cosx + cosx/cosx) (sinx/cosx) / (1+cosx / cosx) sinx / (1+cosx) Step C (left side) (1 - cosx) / sinx (1-cosx)sinx / sin^2x (1-cosx)sinx / (1-cos^2x) pythagorean property (sin^2x + cos^2x = 1) (1-cosx)sinx / (1+cosx)(1-cosx) factor the bottom (sinx / (1+cosx) Cancel the common (1-cosx) secx-1 / tanx = sinx / (1+cosx) Step A Step C backwards of Step B

OpenStudy (anonymous):

my teacher said: To prove an identity you are required to show that the LHS of the relationship given is = the RHS. It is different to solving an equation. You cannot take terms across the = and you cannot multiply or divide both sides by anything. You do so by using accepted identities that enable you to rewrite one or both sides so that they are exactly the same. i dont know what she is asking and what i did wrong please help

OpenStudy (anonymous):

any one please help me

OpenStudy (anonymous):

@perl hi could u please tag other math experts i dont know anyone here

OpenStudy (anonymous):

@kittiwitti1

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