what length of soled cylinder 2 cm in diamatre must be taken to recast into a ahollow cylinder of external diametre 20cm,0.25cm thick and 15cm long?
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OpenStudy (anonymous):
@kittiwitti1
OpenStudy (kittiwitti1):
Oh. Uh....
Can't help you with that. e_e
@hartnn
OpenStudy (anonymous):
why cany u help me with this??
OpenStudy (anonymous):
cant*
OpenStudy (kittiwitti1):
I suck at geometry.
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OpenStudy (anonymous):
ok?
OpenStudy (kittiwitti1):
I'm gonna afk for 20 minutes while I try to solve this. e_e;
OpenStudy (anonymous):
...
OpenStudy (kittiwitti1):
I told you I suck at geometry....
OpenStudy (anonymous):
thanks anyways
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OpenStudy (kittiwitti1):
np e_e
OpenStudy (kittiwitti1):
When you say "0.25 cm thick" do you mean width?
OpenStudy (anonymous):
idk
OpenStudy (kittiwitti1):
....how am I supposed to give you the correct answer then
OpenStudy (anonymous):
i haven't understood the sum
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OpenStudy (kittiwitti1):
Sum?
OpenStudy (kittiwitti1):
|dw:1419599779576:dw| does this sound accurate?
OpenStudy (perl):
so the solid cylinder is melted down and recast into a hollow cylinder
OpenStudy (perl):
and you want know how much solid cylinder (in length) do you need to melt down and recast into the hollow cylinder.
OpenStudy (kittiwitti1):
I think I got the answer...
this is when I wish I had a draw tablet e_e;
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OpenStudy (perl):
helps to draw the hollow cylinder
OpenStudy (kittiwitti1):
I did on my paper. xD
OpenStudy (anonymous):
?
OpenStudy (kittiwitti1):
You know what, listen to @perl... she's the expert xD
(You are a she right e_e?)
OpenStudy (perl):
I am using formula
Volume = Pi * r^2 * h
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OpenStudy (perl):
|dw:1419600851029:dw|
OpenStudy (anonymous):
now?
OpenStudy (anonymous):
@perl
OpenStudy (anonymous):
100-64?
OpenStudy (anonymous):
24*15?
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OpenStudy (anonymous):
thats no answer
OpenStudy (anonymous):
in my book its 74.06
OpenStudy (perl):
there was a typo
OpenStudy (anonymous):
?
OpenStudy (perl):
Volume of solid cylinder
formula : V = Pi * radius^2 * height
substitute:
V1 = pi * (1)^2 * h
Volume of hollow cylinder:
formula : V = Pi * (outer_radius^2 - inner_radius^2 ) * height
substitute
V2 = pi * [ 10^2 - (10 - .25)^2 ] * 15
From the problem we must have V1 = V2
Pi * (1)^2 * h = pi * (10^2 - (10 - .25)^2 )*15
divide both sides by Pi
1* h = [ 10^2 - (10 - .25)^2 ] * 15
h = ( 10^2 - (10 - .25)^2) * 15
h = ( 10^2 - 9.75^2 ) * 15
h = ( 100 - `95.0625`) * 15
h = `4.9375` * 15
h = 74.0625