Question

I need help with a distance/rate/time question.
Lisa leaves her house for a road trip and drives at a rate of 50 mph. Keisha leaves her house 1 hour later and drives along the same route at a rate of 60 mph. At any given time t, the distance traveled can be calculated using the formula d = rt, where d represents distance and r represents rate. Which system of equations can be used to find how long after Lisa departs her house she is passed by Keisha?

Answer 1

do we make the system or is it given as multiple choice?

Answer 2

d=50t
d=60t-1

d=50t
d=60(t-1)

d=50t
d=59t

d=50(t-1)
d=60t

@dtan5457

Answer 3

Let t represent time

you know that keisha is going 60 mph, but an hour later. which of these represent that?

Answer 4

50t does not change.

Answer 5

@GodGirl360

Answer 6

60(t-1)

Answer 7

@dtan5457

Answer 8

Yep.

Answer 9

d=50t d=60(t-1)

you can even test this.

50t=60(t-1)

50t=60t-60

t=6

50 times 6=300
60(6-1)=300

there are on the same level at this point, which keisha will pass any second from the 6 hour mark

Answer 10

Since that equation is only in B, that will be the answer.
d=50t - Lisa drove 50mph for t hours.
d=60(t-1) - Keisha drove 60mph for t hours an hour after Lisa drove.

Answer 11

yes. and 6 will be the numerical answer

Answer 12

Ok, Thank you.

Answer 13

np :)