PLEASE HELP ALGEBRA 2! What is a solution of x^2 - 7x = -5?
Make it a quadratic so x^2-7x+5=0
Do you know how to solve these?
Nope. But I have to submit this in 2 minutes so I have to hurry :/
well luckily for you this one is unfactorable so you have to complete the square or quadratic formula..
let me do it on paper..
Ok...
is this really due in 2 minutes ??
Yep. Actually 1 minute now...
Well now the time is up :/
Sorry...do you still want the answer to know how to do this?
Yes please.
Ok, let me write it out for you
Thanks.
x^2-7x+5=0 since it is unfactorable, you must complete the square. 1.subtract c value to both sides (5) you get x^2-7x=-5 To get a new c value that factorable, you use the formula (b/2)^2 -7/2=3.5^2=12.25 add that to both sides and you get: x^2-7x+12.25=7.25 factor the trinomial which would be (x-7/2)^2=7.25 take out the square by making it x-7/2=the square root of 7.25 add the -7/2 to the other side to get
\[x= \frac{ 7 }{ 2 }\pm \sqrt{29/4}\]
@vera_ewing
I don't know if you ever did this before, but it might be a pain to understand (it took forever for me to get )
Ok that all makes sense but what would be the answer?
the equation i just posted ^^
But that isn't one of my answer choices...
Post your answer choices
https://lss.brainhoney.com/Resource/22181721,AB4,0,B,0,0/Assets/71814_53b5a586/03_07_05a_1.gif
https://lss.brainhoney.com/Resource/22181721,AB4,0,B,0,0/Assets/71814_53b5a586/03_07_05a_2.gif
https://lss.brainhoney.com/Resource/22181721,AB4,0,B,0,0/Assets/71814_53b5a586/03_07_05a_3.gif
https://lss.brainhoney.com/Resource/22181721,AB4,0,B,0,0/Assets/71814_53b5a586/03_07_05a_4.gif
Those are all of my answer choices ^
It looks like they used the quadratic formula instead of completing the square, let me try with the quadratic formula.
Ok
If you use quadratic formula your final answer would be the second link you posted.
Thank you so much. I really appreciate your help :)
Both completing the square and quadratic formula work, so both my answers are theoretically correct, but in this case they used the quadratic formula...which is actually a billion times easier in this case. My bad.
That's alright :) thanks for taking the time to do it both ways!
No problem, feel free to tag me into any more questions you may have :)
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