Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Use the given graph to determine the limit, if it exists.

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 @Hero @saifoo.khan

OpenStudy (anonymous):

well it is a piecewise function, so there mist be a domain and range that have a few restrictions.

OpenStudy (anonymous):

my answer choices are 1.3 -1 4 5 none of these made sense to me so that's why im asking

OpenStudy (anonymous):

Can you find the domain and the range of both functions?

OpenStudy (anonymous):

You are right. Those are values not limits.

OpenStudy (anonymous):

like the limit seems to be 2.5 or around 3 or something...

OpenStudy (anonymous):

you should have answers in parentheses to show the limits. ok. an open circle means that it is not included in the range or domain

OpenStudy (anonymous):

I would say 1.3, because 2 is not included.

OpenStudy (anonymous):

ohh where are human calculators. I am a biology guy. Are you in pre-calculus

OpenStudy (anonymous):

lol ya... but thanks for trying to help anyway:)

OpenStudy (anonymous):

same...

OpenStudy (paxpolaris):

you want to find: \[\large \lim_{x \to 2^-}f(x)\] ...that's the limit of f(x) as the graph x=2 from the left |dw:1419708250093:dw|

OpenStudy (anonymous):

That must be a huge explanation :)

OpenStudy (paxpolaris):

...that's the limit of f(x) as the graph ***approaches x=2 from the left the actual value of \(f(2)\) is \(-1\) ... that doesn't matter. we care about the value f(x) seem to be approaching as x gets to 2 from the left|dw:1419708576442:dw| 1.3 is correct :)

OpenStudy (anonymous):

SWEET!

OpenStudy (paxpolaris):

|dw:1419708831215:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!