Where does the graph of y = sin x from x = 0 to x = 2π start? somebody please help :(

Question

bohotness · Answer

what do you think it is ?

anonymous · Answer

I have no idea, that why I need help

bohotness · Answer

okay i help you

anonymous · Answer

Okay

anonymous · Answer

the option are

a. at its minimum 
b.at an x-intercept
c. at its maximum
d. between an x-intercept and its maximum

but I don't know how to get to the answer, and that's what I need help with

jim_thompson5910 · Answer

when you replace x with 0, in the equation y = sin(x), what do you get?

jim_thompson5910 · Answer

specifically, what is the value of y when x = 0 ?

anonymous · Answer

uh, I have no idea

jim_thompson5910 · Answer

y = sin(x)

y = sin(0) ... replace x with 0

y = ??? ... use a calculator to evaluate the sine of 0

anonymous · Answer

its 0

jim_thompson5910 · Answer

correct, y = 0 when x = 0

jim_thompson5910 · Answer

so because y = 0, we know that there is an x-intercept here

x-intercepts occur when y = 0

anonymous · Answer

so it meets at its x-intercept? Or inbetweeen the x and its maximum?

jim_thompson5910 · Answer

it meets at its x-intercept since it crosses the x axis (y = 0 when that happens)

all x-intercepts are points on the curve and on the x axis

jim_thompson5910 · Answer

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jim_thompson5910 · Answer

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