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Calculus1 21 Online
OpenStudy (jessicawade):

Graph problem help please?

OpenStudy (jessicawade):

Describe the graph of the function g by transformations of the base function f. g(x) = ƒ(3x) g(x)=f(x/2) g(x)=f(x/3) g(x) = ƒ(2x)

OpenStudy (jessicawade):

OpenStudy (tkhunny):

Please tell us what you think.

OpenStudy (jessicawade):

hmm i think its the last one

OpenStudy (tkhunny):

g(6) = f(2) = f(6/3) Rethink.

OpenStudy (jessicawade):

hmm

OpenStudy (jessicawade):

second?

OpenStudy (tkhunny):

You'll need a denominator of 3.

OpenStudy (jessicawade):

hmm this is confusing >_< is the denomiator for the answer 3?

OpenStudy (jessicawade):

a denomenator of 3 means the bottom would be 3 right?

OpenStudy (tkhunny):

g(x) = ƒ(3x) -- 3 in the numerator. g(x)=f(x/2) -- 2 in the denominator. g(x)=f(x/3) -- 3 in the denominator. g(x) = ƒ(2x) -- 2 in the numerator.

OpenStudy (jessicawade):

so the third one?

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