Mathematics
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OpenStudy (jessicawade):
Complex fraction help?
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OpenStudy (jessicawade):
simplify the complex fraction
K+7 over K^2+5k+6 over K+6+ over K+2
OpenStudy (dtan5457):
put that in equation form please
OpenStudy (dtan5457):
i bet i can solve this i literally just learned this
OpenStudy (jessicawade):
its literally that lol it wont let me
OpenStudy (dtan5457):
lets see
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OpenStudy (jessicawade):
OpenStudy (dtan5457):
\[\frac{ \frac{ k+7 }{ k^2+5k+6 } }{ \frac{ k+6 }{ k+2 } }\]
OpenStudy (jessicawade):
yeah lol
OpenStudy (dtan5457):
alright here is what you do. it's not even a complex fraction basically
OpenStudy (dtan5457):
take the "denominator" and flip it so you can multiply it with the numerator
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OpenStudy (dtan5457):
let me write it out
OpenStudy (dtan5457):
\[\frac{ k+7 }{ k^2+5k+6 }\times \frac{ k+2 }{ k+6 }\]
OpenStudy (dtan5457):
now, you want to see what terms you can cross out here
OpenStudy (jessicawade):
ok i had trouble with these so i might get it wrong
OpenStudy (dtan5457):
it's best if you factor our the k^2+5k+6
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OpenStudy (dtan5457):
which are...?
OpenStudy (jessicawade):
I wanna say
OpenStudy (jessicawade):
OpenStudy (dtan5457):
as your answer?
OpenStudy (dtan5457):
to get an answer you must factor k^2+5k+6
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OpenStudy (dtan5457):
what 2 numbers add up to 5 and multiply to 6?
OpenStudy (jessicawade):
3 and 2?
OpenStudy (jessicawade):
sorry im dumb lol
OpenStudy (dtan5457):
good. therefore k^2+5k+6=(k+2)(k+3)
OpenStudy (jessicawade):
amazing with history, stupid with math xD
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OpenStudy (jessicawade):
ohhh
OpenStudy (jessicawade):
so did i get my answer correct
OpenStudy (dtan5457):
\[\frac{ k+7 }{ (k+2)(k+3) }\times \frac{ k+2 }{ k+6 }\]
OpenStudy (dtan5457):
what terms are the same with one in the numerator and denominator?
OpenStudy (dtan5457):
note: you can cross out 2 terms if one appears on the numerator and denominator
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OpenStudy (jessicawade):
well they all are K+ something which is what confuses me lol
OpenStudy (dtan5457):
that also has the same number after it?
Nnesha (nnesha):
okay its call headphone method |dw:1419740601534:dw|
multiply a and c first