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OpenStudy (anonymous):
do u mean
f(2x) = 16x^3 + 20x
OpenStudy (crashonce):
ye
OpenStudy (anonymous):
let
v=2x
x=v/2
then
f(v) - 16(v/2)^3 + 20(v/2)
OpenStudy (anonymous):
typo
f(v) = 16(v/2)^3 + 20(v/2)
OpenStudy (anonymous):
got the idea ?
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OpenStudy (anonymous):
so you would have
this function
f(v) = 16(v/2)^3 + 20(v/2)
find when v=3x :)
hartnn (hartnn):
1. from f(2x), replace x by x/2 to get f(x)
2. from f(x), replace x by 3x to get f(3x)
or you could combine both the steps above to :
replace x by 3x/2 to get f(3x) from f(2x)
OpenStudy (crashonce):
@hartnn how would it go, can u show me
hartnn (hartnn):
go with easier method first...
find f(x) from f(2x)
by replacing all 'x' in f(2x) by 'x/2'
hartnn (hartnn):
like if i say replace x by \(\heartsuit\) in f(2x)
you would do :
\(f (2\heartsuit) = 16\heartsuit^3 + 20 \heartsuit \)
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