. A local min of y=x^3+2x^2-1 is?
2.The y-intercept of y=x^3+2x^2-1 is?
3.The y-intercept of y=x^2+4x-2 is?

Question

. A local min of y=x^3+2x^2-1 is?
2.The y-intercept of y=x^3+2x^2-1 is? 
3.The y-intercept of y=x^2+4x-2 is?

anonymous · Answer

In order to find the local min of a funtion y=f(x), take the first derivative of f(x) and equal to 0, find the x value that solves that and plug it back on f(x) to find the minimum

anonymous · Answer

Also, this same procedure is used to find max

anonymous · Answer

Y-intercept is the point in which x=0, so... plug x=0 and find y.

solomonzelman · Answer

calculus isn't the only way, although for some, it is certainly fastest one. http://mathforum.org/library/drmath/view/62730.html shows an example of how to find the local minimum of a cubic function. I myself though, would prefer to use calc for it