How do you find the point on a line and the slope from an equation in standard form: Ax+By=C?
to find the slope you should solve for y first
slope intercept form equation is should look like this y=mx+b here m is slope and y is y-inrercept
Well the slope is equal to -A/B
for y=mx+b the slope is m right?
Y-intercept is C/B
oh ok
Yes, the slope (m)= -A/B
yes right which always with x
to solve this equation Ax+By =C first subtract ax both side
then divide both side by B
okay then divide b to get y by itself
yes right
\[\Large Ax+By=C\] \[\Large By= -Ax+C\] \[\Large y= \frac{ -A }{ B }x+\frac{ C }{B}\]
let me know what you get :)
well nvm you already got answer
where \[\Large y=mx+b\] is the same as \[\Large y= \frac{ -A }{ B }x+\frac{ C }{B}\]
Ohkay this makes sense
\[\Large m=\frac{ -A }{ B }\] \[\Large b=\frac{ C }{ B}\]
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