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OpenStudy (anonymous):
How do you find the point on a line and the slope from an equation in standard form: Ax+By=C?
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Nnesha (nnesha):
to find the slope you should solve for y first
Nnesha (nnesha):
slope intercept form equation is should look like this y=mx+b here m is slope and y is y-inrercept
OpenStudy (anonymous):
Well the slope is equal to -A/B
OpenStudy (anonymous):
for y=mx+b the slope is m right?
OpenStudy (anonymous):
Y-intercept is C/B
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OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
Yes, the slope (m)= -A/B
Nnesha (nnesha):
yes right which always with x
Nnesha (nnesha):
to solve this equation Ax+By =C
first subtract ax both side
Nnesha (nnesha):
then divide both side by B
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OpenStudy (anonymous):
okay then divide b to get y by itself
Nnesha (nnesha):
yes right
OpenStudy (anonymous):
\[\Large Ax+By=C\]
\[\Large By= -Ax+C\]
\[\Large y= \frac{ -A }{ B }x+\frac{ C }{B}\]
Nnesha (nnesha):
let me know what you get :)
Nnesha (nnesha):
well nvm you already got answer
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OpenStudy (anonymous):
where
\[\Large y=mx+b\]
is the same as
\[\Large y= \frac{ -A }{ B }x+\frac{ C }{B}\]
OpenStudy (anonymous):
Ohkay this makes sense
OpenStudy (anonymous):
\[\Large m=\frac{ -A }{ B }\]
\[\Large b=\frac{ C }{ B}\]
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