Select one of the factors of 3x2 + 4x - 4. (x + 4) (3x + 2) (3x - 2) (x - 2)
can you find 2 numbers whose sum is +4 and product is 3(-4) = -12 ?
wait what? lol i remember something about that but can you explain as to what exactly i have to do?
sure :) to factor \(ax^2+bx+c\) we split the middle term : bx by finding 2 numbers with sum as +b and product as ac
so for \(3x^2 +4x-4\) we need to split 4x find 2 numbers with sum as +4 and peoduct as -12
*product
I see why you would try to find 4 but why -12?
oh wait is it becuase you have to multiply 3 & 4
yes ac = 3(-4) =-12 so that we would be able to factor out the quadratic into 2 factors properly
oh okay that makes sense.
so... can you find 2 numbers whose sum is +4 and product is 3(-4) = -12 ?
hint : one number is negative, other is positive
6\[6-2=4 and 6\times-2\]
good! so we split 4x as \(\large 4x =6x -2x\)
\(\Large 3x^2 +6x-2x-4\) what can you factor out from 1st 2 terms \(3x^2 +6x\) ??
sorry i had to answer the phone
\(\Large 3x^2 = 3x (x) \\ \Large 6x = 3x(2)\) no problem!
this is where i get stuck. so would you do this?
\[3x(x+2)?\]
yes!
so, now take last 2 terms -2x-4 what can you factor out ?
-2(x-2)?
-4 is actually -2(+2) not -2(-2)
oops sorry
so \(\Large -2x-4 = -2 (x+2)\) makes sense ?
yes
we have now \(\large 3x\color{blue}{(x+2)} -2 \color {blue}{(x+2)}\) what can be factored out ??
(x+2)(3x-2)?
\(\Huge \checkmark \)
awesome thank you!!!
welcome ^_^
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