Question

ALGEBRA 1, PLEASE HELP. REWARDS WILL BE GIVEN.
The graphs of functions f(x) and g(x) = f(x) + k are shown below:
graph of line f of x going through ordered pairs 0, negative 2 and 2, 2. Graph of line g of x going through ordered pairs 0, 2 and 1, 4.
The value of k is ___.
Numerical Answers Expected!
Answer for Blank 1:

Answer 1

Is the question complete? Just wondering since the blue asks box trails

Answer 2

no that's the full question.
@Sadworld

Answer 3

I see now, give me a moment

Answer 4

okay. take your time. :)

Answer 5

f(x) = (x+k)+k
f(x) = x+2k

0+2k = -2 (x, y of first order of pairs)
k = -2/-2
k = -1

Answer 6

thank you so much!@Sadworld

Answer 7

wait, a min. Still proving

Answer 8

You got an answer sheet?

Answer 9

yes.

Answer 10

So -1 is correct?

Answer 11

no

Answer 12

Okay, lemme try another version.

Answer 13

I got the substitutions wrong. f(x) = y so

f(x) = f(x) + k
-2 = -2 + k (y coordinate of the first pair)
k = 1

Answer 14

@Directrix @ganeshie8

Answer 15

hi Directrix, so I end up with k = 1. Wondering if I got it right.

Answer 16

No diagram?

Answer 17

@Sadworld Did you get the equation for f(x) to be y = 2x -2 ?

Answer 18

mmm... I got on my first try f(x) = x + 2k;
On the 2nd try f(x) = y + k

Answer 19

And, the equation of g(x) = 2x + 2.

From -2 to + 2 = 4 units for k but I need to make a graph because k may be -4.

Answer 20

One part of the problem I encounter is the question. So [f(x) = f(x) + k] is wrong?

Answer 21

Look at the attached graphs from the Wolf.

http://www.wolframalpha.com/input/?i=y+%3D+2x+%2B+2%2C+y+%3D+2x+-+2

Answer 22

I knew it, I misunderstood the question.

Answer 23

I know what you are saying. That is why I asked to see the graph that came with the original problem.

f(x) and g(x) = f(x) + k are the two graphs.

This is not part of the problem: [f(x) = f(x) + k]

Answer 24

If the OP will post the original diagram, I'll reconsider. If not, I'm sticking with k = 4.

It is as correct as I can figure. What do you think @Sadworld and what does

@grunge101 think. Offline, it seems.

Answer 25

@kittiwitti1 Let us hear what you think, okay? All ideas are welcome and appreciated.

Answer 26

I agree with you, I just jumbled to the question and thought that part was included to the whole thing.

Answer 27

I'm only on this to avoid getting repeated notifications about this question.

Answer 28

Lol I'm not inputting anything.

Answer 29

lols

Answer 30

OP will be so pissed to see all the additional chatter *laughs*

Answer 31

Look at my "wolf" graph. @kittiwitti1 The two functions are parallel and 4 apart?

Answer 32

I'm not saying that our OP did this but many OPs post a question and then run off.

Answer 33

Wolf graph?

Answer 34

Ah, that.

Answer 35

http://www.wolframalpha.com/input/?i=y+%3D+2x+%2B+2%2C+y+%3D+2x+-+2

Answer 36

I am not participating in this.
I am only here to minimize the notifications I get from this question lol

Answer 37

Sorry to be a bother. *bows*

Answer 38

I don't understand that @kittiwitti1

Answer 39

You get computer messages if you participate in a question, participate in many you get overloaded by computer generated messages ie Spam

Answer 40

Pretty much what Sadworld said, yes.

Answer 41

Yes. But, I did not see the KW's name pinged in the thread.
The OP did not ping me over here either.

Answer 42

I asked Kitti for referrals since I only have 3 names i can refer

Answer 43

Yep. :p

Answer 44

Look at this. I found the solved problem AND the original diagram.

http://openstudy.com/study#/updates/5398778de4b03871bbf0b21e

Answer 45

>>I asked Kitti for referrals since I only have 3 names i can refer

I have seen people ping 12 people at the time. Why are you limited to three?

Answer 46

My god, you actually spend time to dig it up o.o dedication.

Answer 47

@Directrix I only ping people I know who are good ;)

Answer 48

Well, that is flattering.

Answer 49

We can close this up now with a big FOUR, can't we?

Answer 50

Correct.

Answer 51

The answer is \[k = 4\]

Answer 52

Let's go here and help.

http://openstudy.com/study#/updates/54a2debee4b0a96030d794d1