ABCD is a quadrilateral inscribed in a circle: Circle O is shown with a quadrilateral ABCD inscribed inside it. Angle A is labeled x plus 16. Angle B is labeled x degrees. Angle C is labeled 6x minus 4. Angle D is labeled 2x plus 16. What equation can be used to solve for angle D? (2x + 16) + (6x - 4) = 90 (x + 16) - (x) = 90 (x + 16) + (2x + 16) = 180 (2x + 16) + (x) = 180
I think D..
@Directrix
Theorem: Opposite angles of a quadrilateral inscribed in a circle are supplementary.
Meaning they add up to 180 degrees..
Correct. Here's a reference on that theorem: http://www.geom.uiuc.edu/~dwiggins/conj47.html
So my answer is Correct..
*Correct..?
Angles B and D are opposite angles. So, yes, this equation is correct. (2x + 16) + (x) = 180
Okay, thanks.
You are welcome.
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