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can someone please explain this to me?
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\[\frac{d}{dx}\int_a^b f(x)dx = F(b)-F(a)\]
\[f(x) = R(t) = 2+\cos\left(\frac{\pi t}{11}\right)\]
can someone pleaseee do the problem with me cause i really dont understand this
okk
wait so i just put in 0 for t?
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no do not integrate, that is already a function in gal/hr, use that and plug in the value for house
hours
You could just evaluate at R(6) - R(0)....
^ yep
\[\frac{d}{dx}\int_a^b f(x)dx = F(b)-F(a) = \left. 2+\cos\left(\frac{\pi t}{11}\right) \right|_0^6=~?\]
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\[\left. 2+\cos\left(\frac{\pi t}{11}\right) \right|_{t=0}^{t=6}=~?\]
Hope that helps
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