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Pre-Algebra
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Solve for h. P = mgh A. h = P – mg B. C. D. h = P + mg
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To solve for 'h' we have to get rid of 'mg'. 'mg' is being MULTIPLIED to 'h', so in order to get rid of it, we must do the opposite. And what's the opposite of multiplication?
division
Right, so divide 'mg' to both sides, what do you get?
p/mg and h/mg
right?
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h= p/mg?
You got it! :D
thankyou
\(P = mgh\) Divide mg to both sides: \(\dfrac{P}{mg} = \dfrac{mgh}{mg}\) \(\dfrac{P}{mg} = \dfrac{\cancel{mg}h}{\cancel{mg}}\) The mg's to the right cancel out leaving you with: \(h = \dfrac{P}{mg}\)
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