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@Michele_Laino
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@hartnn (:
dy/dx at x=-1,y=1 \(\Large \dfrac{xy}{3} = \dfrac{1\times -1}{3} = \dfrac{-1}{3}\) thats your first entry calculate all other entries in a similar manner by plugging in corresponding x and y values in xy/3
it is always over 3?
its in the question,so yes
so the second one would be -2/3?
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this looks way too easy..
correct
it is wayyy to easy
hahha okay thanks
welcome ^_^
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wait so the 4rth-9th boxes would just be 0?
@hartnn
the 4rth-6th*
yes if any one of the x or y is 0, then the entry = 0
okay just making sure, it sounds way to easy for calc hahahah
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the question to follow, 2,3 might not be so easy :) 1.st one is just the part of 1 big question :P
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