The slope of the line below is 3. Use the coordinates of the labeled point to find the point-slope equation of the line. (6,8) A. y - 6 = -3(x - 8) B. y - 8 = -3(x - 6) C. y - 8 = 3(x - 6) D. y - 6 = 3(x - 8)
point slope form is \[y-y _{1}^{?}=m(x-x _{1}^{?})\] *ignore the Q marks
What are the points on the line?
(6,8)
sub in the points on for y1 and x1, then sub 3 in for m. What'd ya get?
hold on one sec
ok sorry my dog wanted to go outside. so replace y with 6 and x with 8? or replace the 1's?
ok this is something idk exactly how to do
There are 2 diffrent xs and 2 diffrent ys in the point slope equation. They only want you to use one right now. What I was trying to say is. \[y _{1}=6\] \[x _{1}=8\] and \[m=3\] in \[y-y _{1}=m(x-x _{1})\] sub them and what do ya get?
well 6-8 =-2
Ohhhhh. wait it would be A.
Sorry no all you have to do is substitute, not subtract. so y- ____=____(x-_____)
y - 6 = -3(x - 8) So it wouldn't be that but replace y with 6 and x with 8?
Yes
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