A student found the slope of a line that passes through the points (3, 15) and (5, 9) to be-1/3 . What mistake did he make? A. He did not make a mistake. That is the correct slope. B. He used the negative reciprocal of the slope. C. He added a negative sign. D. He used the reciprocal of the slope.
someone please help!
ok so do you know point-slope formula
no?
welll, what's the sloppe it anyway? \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 3}}\quad ,&{\color{blue}{ 15}})\quad &({\color{red}{ 5}}\quad ,&{\color{blue}{ 9}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\) what would that give you for the slope?
listen to @jdoe0001 i got it mixed up
@Tallan just substitute and solve
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