Question

Find the zeros of the function. State the multiplicity of multiple zeros. y = x(x - 1)3

x = 9 multiplicity 2
x = 0, x = 1 multiplicity 3
x = 0 multiplicity 2
x = 1 multiplicity 3

Answer 1

If: \(\large\color{slate}{ 0=a\times b\times c \times d }\)

then: \(\large\color{slate}{ a }\) , \(\large\color{slate}{ b }\) , \(\large\color{slate}{ c }\) , or \(\large\color{slate}{ d }\) is zero.

Answer 2

you have a similar case:
\(\large\color{slate}{ 0=x(x-1)^3 }\) (writing \(\large\color{slate}{ 0 }\) instead of \(\large\color{slate}{ f(x) }\) since you want to find the zeros)

Answer 3

hint: \(\large {
y = x(x - 1)^3
\\ \quad \\
0= x(x - 1)^3\to
\begin{cases}
0=x\\
0=(x-1)^3\to 0=(x-1)(x-1)(x-1)
\end{cases}
}\)

Answer 4

you have a similar case:
\(\large\color{slate}{ 0=x(x-1)^3 }\) (writing \(\large\color{slate}{ 0 }\) instead of \(\large\color{slate}{ f(x) }\) since you want to find the zeros)

Answer 5

so D i think

Answer 6

what are the zeros, of the functions?
which of the options has them/it listed?

Answer 7

i forgot about the other x gah but this helped me a lot thank you @SolomonZelman

Answer 8

Oh, surely:) I can see you got this this....
This is what I am here for; not a problem!