Question

The base of a rectangular solid is 4ft. long and 3ft. wide. Find the volume of the solid if its diagonal is sqrt of 41 ft.

Answer 1

is sqrt of 41 the diagonal of the solid? or the face?

Answer 2

Do you have choices? I suspect this is the diagonal of the solid. If you have choices, is one of the choices, is one 48 cubic ft.?

Answer 3

The diagonal of the base is 5 which is not the square root of 41.

Answer 4

none
im just confuse if what kind of diagonal it is

Answer 5

so the height is 4 ft?

Answer 6

and the volume is 48ft.?

Answer 7

Now let the height be x, then\[\sqrt{5^{2}+x ^{2}}=\sqrt{41}\]Can you take it from there?

Answer 8

Yes, that is correct.

Answer 9

If you solve the equation I posted in my previous post, x = 4

Answer 10

i used \[h=\sqrt{d²-l²-w²}\]

Answer 11

thank you:)

Answer 12

I am not an artist

Answer 13

thanks

Answer 14

You're welcome, if you look hard enough, you will see that the solid diagonal is the hypotense of another right triangle consisting of sides x and the diagonal of the base.

Answer 15

ok