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OpenStudy (anonymous):
URGENT PLEASE RESPOND FAST!
Find the solutions of g(x). Show each step.
• g(x) = x^2 +6x + 1
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OpenStudy (alexandervonhumboldt2):
use quadratic formula
OpenStudy (radar):
One solution is (1,8) or are you wanting the values of x when g(x) = 0
OpenStudy (alexandervonhumboldt2):
i gues they mean x values
OpenStudy (alexandervonhumboldt2):
-3+-2sqrt2
OpenStudy (radar):
I'm not sure, but the quadratic will work......it cant be factored.
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OpenStudy (alexandervonhumboldt2):
\[-3\pm2\sqrt{2}\]
OpenStudy (anonymous):
I'm not sure radar, the question wasn't specific
OpenStudy (alexandervonhumboldt2):
(-6+-sqrt(36-4))/2
OpenStudy (alexandervonhumboldt2):
(-6+-4sqrt2)/2
OpenStudy (alexandervonhumboldt2):
=-3+-2sqrt2
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OpenStudy (alexandervonhumboldt2):
i guess they mean x because it is finite number of solutions
OpenStudy (radar):
well there is an infinite number of values that x can take on, thus an infinite number of points in the function.
OpenStudy (anonymous):
tyvm alex
OpenStudy (radar):
I like the method where you complete the square to find the zeroes. What part of math are you currently studying.
OpenStudy (anonymous):
Alex seems to have gotten the answer I was looking for
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OpenStudy (alexandervonhumboldt2):
ok
OpenStudy (anonymous):
Radar I'm in algebra 2 :)
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