Question

I'm having a little trouble figuring this out, can someone help?

Melissa bought a new car with 12 optional features to the car. Each optional feature costs either $23.99 or $120.84. If she paid $675.28 for all the optional features, how many of each type did she buy? Write and solve an equation to solve this problem. Show all your work.

Answer 1

Okay, let:

Number of the purchases first feature \(\normalsize\color{royalblue}{ \rm F_1 }\)
Number of the purchases second feature \(\normalsize\color{royalblue}{ \rm F_2 }\)

\(\normalsize\color{royalblue}{ \rm F_1+F_2 =12 }\)
\(\normalsize\color{royalblue}{ \rm (23.99)F_1+(120.84)F_2 =120.84 }\)

Answer 2

mstake

Answer 3

Your system should look like this.

\(\normalsize\color{royalblue}{ \rm F_1+F_2 =120.84 }\)
\(\normalsize\color{royalblue}{ \rm (23.99)F_1+(120.84)F_2 =675.28 }\)

Answer 4

you can use \(\normalsize\color{royalblue}{ \rm x }\) for \(\normalsize\color{royalblue}{ \rm F_1 }\) AND \(\normalsize\color{royalblue}{ \rm y }\) for \(\normalsize\color{royalblue}{ \rm F_2 }\)

Answer 5

@SolomonZelman Thank-You!

Answer 6

yw

Answer 7

@SolomonZelman
I think you mean:
\(\normalsize\color{royalblue}{ \rm F_1+F_2 =12 }\)

Answer 8

yes, that too... it's a day of mistakes (as always)

Answer 9

this is the system: \(\normalsize\color{royalblue}{ \rm F_1+F_2=12 \color{white}{\Huge|} }\)
\(\normalsize\color{royalblue}{ \rm(23.99)F_1+(120.84)F_2=120.84 }\)

Answer 10

Hello and welcome to OpenStudy @Zoe9639 :) Since your question has been answered, you should close it so other users know that it has been answered! :) Do you know how to close your question? Also, you can't post another question in this subject until you have closed this one.

Answer 11

@sammixboo thank you! I forgot :)

Answer 12

No problem, and it's okay!