which of the following is the equation of a line perpendicular to the line Y= -3/2x+4 and passes through the point (3,9)
A) -2x-3y=-21
B) -2x+3y=21
C) 2x+3y=21
D) 2x-3y=21
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OpenStudy (misty1212):
a) find the slope of \(y=-\frac{3}{2}x+4\)
well you don't really find it, you just say it
do you know it?
OpenStudy (misty1212):
if you do not, then say so and i will tell you
OpenStudy (anonymous):
-3/2
OpenStudy (misty1212):
ok good
now the perpendicular line will have the slope that is the "negative reciprocal"
what is that?
OpenStudy (anonymous):
3/2
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OpenStudy (misty1212):
you didn't flip it
OpenStudy (anonymous):
2/3
OpenStudy (misty1212):
ok good
now the point slope formula gives
\[y-9=\frac{2}{3}(x-3)\]
OpenStudy (anonymous):
so what do i do next? im confused :(
OpenStudy (misty1212):
write it in standard form
first multipy all by 3 to get
\[3y-27=2(x-3)\] then expand on the left
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OpenStudy (misty1212):
\[3y-27=2x-6\] then put it all on one side of the equal sign
OpenStudy (misty1212):
\[2x-3y=-21\] which is not an option so maybe
\[-2x+3y=21\]