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|X+3| < 5 A) -8 < X < 2 B) -2 < X < 8 C) 3 < X < 5 D) -3 < X < 5
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This is a "less than" absolute value inequality so... -5<x+3<5 -8<x<2
A ?
To solve an absolute value inequality of the form: \(|X| \lt k\) where X is an expression in x and k is a number, solve this compound inequality: \(-k \lt X \lt k\)
For your problem, it goes like this: \(|x + 3| \lt 5\) \(-5 \lt x + 3 \lt 5\) Subtract 3 from all three "sides" to get: \(-8 \lt x \lt 2\)
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