Solve the following system of equations: x - 2y = 14 x + 3y = 9 (1, 12) (-1, -12) (12, -1) (12, 1) @DanJS
for x and y?
x=14+3y x=9-3y
yeah, tons of people responding,, ill sit this one out , less you need help after
14+2y=9-3y
14-9=y
I assume so @jackthegreatest
plug in the numbers and solve the equation, PEMDAS. the first number for x and the second number for y
k
i mistaked somewhere
14+3y=9-3y
Yeah I was kinda confused because you had (4,5) but those aren't options.
@AlexandervonHumboldt2
oh no
i got confused
That's okay we all do @AlexandervonHumboldt2
slow down there alex, it is not a race for medals, well maybe it is for you
I don't know where to start..
First of all, this is my first time ever being on here. This is only my second question so I don't even know how to give medals. I mean unless someone told me how I wouldn't be able to...
Can someone just help me figure it out..
@DanJS
@AlexandervonHumboldt2
x - 2y = 14 x + 3y = 9
Multiply the first equation through by -1. (-1)(x - 2y) = (-1) *14 -x + 2y = -14 all the signes switched
now the two equations are -x + 2y = -14 x + 3y = 9
Add them together, Notice the X cancels out -x + 2y = -14 x + 3y = 9 --------------------- 0x + 5y = -5
You are left with 5y = -5 divide by 5 on both sides y = -1
you really don't have to figure out X in this problem, only one answer choice has y=-1 in (x , y) ---- (x , -1)
Well two of the options has -1.. there's B and C
Each of those answers is a point in the form (x , y) the first spot is the x value, the second spot is the Y value. We found the y value, y=-1, only one answer has -1 in the Y spot
unless it's just C
right , the third one (12 , -1) ...x=12, y = -1
Okay okay that makes sense
Join our real-time social learning platform and learn together with your friends!