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Mathematics 15 Online
OpenStudy (anonymous):

I think the answer is D. but i am not sure! [3.02] If C = {all numbers from 1 to 18} and D = {numbers divisible by 6 from 1 to 12}, what is CintersectionD? Select one: a. {all numbers from 1 to 18} b. {1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17} c. {6, 12, 18} d. {6, 12}

OpenStudy (mathmate):

@jiujitsu4life Is this one of them?

OpenStudy (anonymous):

yeah

OpenStudy (mathmate):

You need to calculate \(C\cap D\). First step: list the members of C and D. Can you do that?

OpenStudy (anonymous):

Yes

OpenStudy (mathmate):

\(C\cap D\) means a set that contains only elements that are present in both sets. For example, A={1,2,3}, B={2,3,6}, then \(A\cap B={2,3}\) because 2 and 3 are the only elements present in both A and B.

OpenStudy (mathmate):

Are you ready to list the elements of C and D?

OpenStudy (anonymous):

YEs

OpenStudy (mathmate):

Can you post the lists, please?

OpenStudy (anonymous):

C=(1,2,3,4,5,6,7,8,9,10,12,13,14,15,16,17,18) and D=(6,12) Y am i doing this???

OpenStudy (mathmate):

Great, perfect! Now choose the elements that are common (present in) both sets C and D. Place braces { } around those numbers and you're done!

OpenStudy (mathmate):

Oh.. Use braces { } to enclose members of a set. This is a mathematical convention.

OpenStudy (mathmate):

To answer you earlier question: I wanted you to post what we're working on, or else we may not be on the same wavelength, since I cannot guess what you have in mind. Sorry that it's an extra 59 seconds of work! :(

OpenStudy (anonymous):

I have an exam and many other things to do, so i am just trying to get through this program i am in. I dont really need exrta work, or crap from people i just wanted a yes or no answer if i was going in the right direction. I already said what i might have though

OpenStudy (mathmate):

I am sorry that I have caused you dissatisfaction! Please understand that we're here to help you understand what you do, not to give you answers. You're almost there, and your answer should be at the tip of your tongue. If you had an answer since the beginning, I would have loved to hear it and have gone from there!

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