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Mathematics 20 Online
OpenStudy (anonymous):

medal and fan please help!!!!!!!!!!!!!

OpenStudy (solomonzelman):

no need for medal and fan, just ask a particular question.....

OpenStudy (anonymous):

A system of equations is shown below: 3x – y = 2 x + y = 6 The x-coordinate of the solution to this system of equations is

OpenStudy (solomonzelman):

I will rejoin to remove question marks

OpenStudy (anonymous):

its a fill in the blank

OpenStudy (solomonzelman):

so you just need to solve for x.

OpenStudy (anonymous):

Thats the problem I dont know how to do that

OpenStudy (anonymous):

its ok I can read them I just pretend their not there

OpenStudy (anonymous):

u there

OpenStudy (solomonzelman):

you have this system below: \(\large\color{royalblue}{ 3x - y = 2 }\) \(\large\color{royalblue}{ x + y = 6 }\)

OpenStudy (solomonzelman):

add the equations together

OpenStudy (anonymous):

wat do u mean

OpenStudy (anonymous):

is it 4x+2y=8?

OpenStudy (solomonzelman):

\(\large\color{royalblue}{~~~~~~3x ~- ~y ~~= 2 }\) \(\large\color{royalblue}{^{^{\color{red}{\Huge+}}} ~~x ~~+ ~y~~ = ~6 }\) \(\large\color{royalblue}{^\text{_________________} }\)

OpenStudy (solomonzelman):

add the x's, the y's and the numbers (2 and 6)

OpenStudy (anonymous):

is it 4x+2y=8?

OpenStudy (solomonzelman):

-y+y = 2y? are you sure?

OpenStudy (anonymous):

oh forgot I didnt see the negative its just y now right so it would be 4x+y=8?

OpenStudy (solomonzelman):

no not exactly.

OpenStudy (solomonzelman):

(your 4x and the 8 are correct)

OpenStudy (anonymous):

4x=8?

OpenStudy (solomonzelman):

yup, the y cancel

OpenStudy (anonymous):

ok so x=2?

OpenStudy (solomonzelman):

\(\large\color{royalblue}{4x=8 }\) , so \(\large\color{royalblue}{x=2 }\). CORRECT!

OpenStudy (solomonzelman):

So, the x-coordinate of your solution is 2.

OpenStudy (anonymous):

and thats it?

OpenStudy (solomonzelman):

yes, you are done with this question:)

OpenStudy (anonymous):

heres your medal and I'll mention you in another question if I need help

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