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Mathematics 21 Online
OpenStudy (anonymous):

which equeation is shown on the graph

OpenStudy (anonymous):

A. y = 2x – 3 B. y = 3x C. y = x – 3 D. y = x + 3

OpenStudy (anonymous):

a is y=2x-3

OpenStudy (michele_laino):

Hint: your graph is the graph of a line. Using the segmentary form for the equation of a line, we can write: \[\frac{ x }{ 3 }+\frac{ y }{ (-3) }=1\] Please simplify that equation

OpenStudy (anonymous):

c is y=x+3

OpenStudy (michele_laino):

no, please multiply both sides of my equation, by 3

OpenStudy (anonymous):

is it b

OpenStudy (michele_laino):

hint: \[3*\frac{ x }{ 3 }+3*\frac{ y }{ (-3) }=3*1\] so: \[x-y=3\] finally: \[y=x-3\]

OpenStudy (anonymous):

so its c

OpenStudy (michele_laino):

then, what is your option?

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

c

OpenStudy (michele_laino):

yes!

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