A first number plus twice a second number is 24. Twice the first number plus the second number is 21. What are the numbers?
x+2y=24 is going to be the equation for the first one....
Can you try to find the second one?
y+2x=21
=24*
but I would word it to where the x term comes first so it is easier :)
oh I typed my first one in wrong, it is actually 21
oh okay :)
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Are they both 21 or is one of them 24 still?
One of them is 24 I edited the original question and fixed it.
okay great! So now that we have both: x+2y=24 2x+y=21 We can now substitute to find the values of x and y :) I can show you the steps if you want?
Ok, I tried a lot of the different combinations of numbers that fit for the first one, but none of them worked for the second one, they were all way too big.
Substitution is not where you replace numbers into x and y, but rather one equation into the other. So first, we need to isolate x for the first one.
Ok so x=24-2y?
Correct! So now that we have that, we can then plug it into the x of the second equation like so: 2(-2y+24)+y=21 Then you need to distribute the 2 to the -2y and 24.
Do you understand what I did there?
-4y+48+y=21
Correct! Then you need to combine like terms.
which can be simplified to -3y=-27
Correct! Then divide both sides by -3
so y=9
so put that into the next equation to solve for x
Yes. Then you can replace y=9 into either one of the equations (It doesn't matter which) and solve
It would be easier to put it into the x=-2y+24 since x is already isolated
x+18=24, so x equals 6!
Thank you so much for the help! :) :)
Yes! Great job! So: y=9 x=6 And that's all! :D
No problem!
Would you mind hitting the 'close' button to close this question? Thank you!
Ok
Thank you!
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