Mathematics
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OpenStudy (darkbluechocobo):
Help with Exponential Growth
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OpenStudy (darkbluechocobo):
OpenStudy (darkbluechocobo):
so intial cost would be 30000?
OpenStudy (xapproachesinfinity):
hmm that easy you just plug in the values
OpenStudy (xapproachesinfinity):
yes it appears so
OpenStudy (darkbluechocobo):
so then V(12)=30000e^12b
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OpenStudy (darkbluechocobo):
so the rate how would you find that?
OpenStudy (xapproachesinfinity):
hmm let me i haven't read carefully the problem
OpenStudy (xapproachesinfinity):
v(5)=v0e^(5b)
solve for b
OpenStudy (xapproachesinfinity):
the v(5) is given to you
OpenStudy (xapproachesinfinity):
v0 is the initial cost which is 30000
v(5) is the cost after five years
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OpenStudy (xapproachesinfinity):
the only unknown you have there is b
OpenStudy (xapproachesinfinity):
once you found b you can finally look for v(12)
OpenStudy (darkbluechocobo):
ohhhh
thank you
OpenStudy (xapproachesinfinity):
eh don't use 30000
in the equation you will get a wrong answer
OpenStudy (darkbluechocobo):
so here would be 12000?
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OpenStudy (xapproachesinfinity):
because the model is already in thousands
OpenStudy (xapproachesinfinity):
yeah v(5)=12 in thousands
OpenStudy (xapproachesinfinity):
do you get it
OpenStudy (darkbluechocobo):
wait so it would just be 12?
OpenStudy (xapproachesinfinity):
correct, since the model is in thousands already
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OpenStudy (xapproachesinfinity):
if you use 12000 and 30000 you will get a wrong b
OpenStudy (xapproachesinfinity):
you can try and see for yourself
OpenStudy (darkbluechocobo):
V(5)=12e^5b
So we have to take the natural log of both sides right?
OpenStudy (xapproachesinfinity):
no v(5)=12
remember v0=30
OpenStudy (xapproachesinfinity):
you set it the wrong way
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OpenStudy (darkbluechocobo):
so just 12?
OpenStudy (darkbluechocobo):
erggg
OpenStudy (darkbluechocobo):
how do we solve for b then?
OpenStudy (xapproachesinfinity):
\(\large v(5)=v_0e^{5b} \Longrightarrow 12=30e^{5b}\)
OpenStudy (xapproachesinfinity):
do you see it now
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OpenStudy (darkbluechocobo):
ohhh so basically the cost difference in the 5 years
OpenStudy (darkbluechocobo):
so would we divide 30 by both sides to start?
OpenStudy (darkbluechocobo):
chu there?
OpenStudy (xapproachesinfinity):
yes
OpenStudy (xapproachesinfinity):
sorry i was away
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OpenStudy (darkbluechocobo):
aha its fine :p
OpenStudy (xapproachesinfinity):
that is easy to solve now!
just divide both side by 30 reduce the lHS fraction and apply ln
OpenStudy (darkbluechocobo):
ok so .4=e^5b
OpenStudy (darkbluechocobo):
now about this how would you go about getting the exponent alone
OpenStudy (xapproachesinfinity):
eh reduce the fraction i said not a decimal
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OpenStudy (xapproachesinfinity):
never go to decimal is they didn't ask you
OpenStudy (darkbluechocobo):
ohhh
sorry it says nearest hundred :p
OpenStudy (xapproachesinfinity):
that would be b not that fraction
OpenStudy (darkbluechocobo):
ohhh
OpenStudy (xapproachesinfinity):
you will get a slightly wrong answer if you round before you reach the answer
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OpenStudy (darkbluechocobo):
but should i keep .4 though
OpenStudy (xapproachesinfinity):
hmm eh if you want to use then go for it!
my way is to just reduce the fraction and then apply ln
OpenStudy (xapproachesinfinity):
2/5 is the reduced fraction
OpenStudy (darkbluechocobo):
alright
OpenStudy (xapproachesinfinity):
\(\Large 2/5=e^{5b} \Longrightarrow \ln(2/5)=5b\)
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OpenStudy (xapproachesinfinity):
well it appears that won't change anything in this case just go ahead and use 0.4
OpenStudy (darkbluechocobo):
yeh i just saw that lool
OpenStudy (darkbluechocobo):
-.91629073
OpenStudy (xapproachesinfinity):
hmm divide by 5
OpenStudy (xapproachesinfinity):
and round the nearest hundred
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OpenStudy (darkbluechocobo):
-.18
OpenStudy (xapproachesinfinity):
hmm sounds good
OpenStudy (darkbluechocobo):
so now we fill this in for b in the 12 year equation
OpenStudy (xapproachesinfinity):
-18/10=-9/5=b
OpenStudy (xapproachesinfinity):
yes!
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OpenStudy (xapproachesinfinity):
use b to find v(t=12)
OpenStudy (darkbluechocobo):
oks V(12)=30000e^12(-.18)
OpenStudy (xapproachesinfinity):
I said use 30 only for 30000
OpenStudy (darkbluechocobo):
Yes i forgot T_T
OpenStudy (darkbluechocobo):
oopsie
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OpenStudy (xapproachesinfinity):
that's okay
OpenStudy (darkbluechocobo):
V(12)=30e^12(-.18) fixed
OpenStudy (xapproachesinfinity):
okay that's good! now compute that
OpenStudy (darkbluechocobo):
oks so 30(.11532512
OpenStudy (xapproachesinfinity):
just do the entire thing! it is just calculator work now
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OpenStudy (darkbluechocobo):
lelel sorry i like writing out steps
OpenStudy (xapproachesinfinity):
once you finished multiply by 1000 to get the answer you are looking for
OpenStudy (darkbluechocobo):
3.46
OpenStudy (darkbluechocobo):
3460?
OpenStudy (xapproachesinfinity):
|dw:1420574019930:dw|
apparently this how your function is acting