Question

How would you write log627 – 2log63 as a single logarithm?

Answer 1

log627- 2log63

Answer 2

please you have to apply this properties:
\[n*\log _{b}x=\log _{b}(x ^{n})\]
and subsequently:
\[\log _{b}x-\log _{b}y=\log _{b}(\frac{ x }{ y })\]

Answer 3

for example, we have \[2\log 63=\log(63^{2})=...\]
please continue

Answer 4

when you subtract logs you divide the numbers
27 can be expressed as 3 * 9 and 63 can be expressed as 7 * 9
when you multiply numbers add the logs
also use the log rule above for exponents.

oops that is not log 63 its log base 6 of 3
so log base 6 of 3^2

Answer 5

27 = 3^3