Question

solve 2x^2+x=15

Answer 1

x=5/2 or x=-3

Answer 2

how did you get that?

Answer 3

\[2x^2+x=15\]Move the 15 over by subtracting -15 from both sides. \[2x^2+x-15=0\]Now factor this. I use the BUM method (don't ask me why it's called that).\[x^2 +x -30=0\]\[(x+6)(x-5)=0\]\[\left(x+\frac{6}{2}\right)\left(x-\frac{5}{2}\right)=0\]\[(x+3)(2x-5)=0\]

Answer 4

Solving for your factors, \[x+3=0 \implies x=-3\]\[2x-5=0 \implies x = \frac{5}{2} \]

Answer 5

Yeah that makes a lot more sense, thanks :)