Question

@Clalgee Help with Trigonometry HW?

Answer 1

Yay! Thanks! I'll post the question, one second.

Answer 2

Alright, do you know how to start?

Answer 3

No, can you just give me the answer??

Answer 4

I'm sorry, but it's against the rules to do that. I wouldn't mind helping you solve the problem.

Answer 5

..... @satellite73 what is the answer? @acxbox22

Answer 6

exactly...@Christine88 direct answers arent permitted here but we all would be glad to help

Answer 7

@Christine88

Answer 8

Then what's the point? -.-

Answer 9

The point is for you to understand the problem. Not to give you the answers to the equation. You don't learn anything when we give you the answers.

Answer 10

Can someone else help me? You guys are making this difficult.

Answer 11

at least attempt the problem, then we can help

Answer 12

you want a mod to help you, lets see...@satellite73 @ganeshie8

Answer 13

Yes, @acxbox22 is right. Try the problem and we will help you from there.

Answer 14

..... Your only going to tell on me.

Answer 15

\(\Huge\cal\color{green}{TRY}\)

Answer 16

I don't know how to do it though... and I have to turn it in tomorrow.

Answer 17

cos=adjacent/hypotenuse

Answer 18

I don't know.

Answer 19

first use pythagorean theorum to find the hypotenuse

Answer 20

Exactly what @acxbox22 said. Use cos= adjacent/hypotenuse

Look at the graph. What is the adjacent angle and what is the hypotenuse angle?

Answer 21

I think the adjacent is RQ and the hypotenuse is PR.... How does this even help me?

Answer 22

You guys aren't even making any sense...

Answer 23

@dan815 @ShadowLegendX @TheSmartOne @ganeshie8 @bibby Someone help me! They aren't making any sense!!

Answer 24

@undeadknight26

Answer 25

lol

Answer 26

?????????????????? How is lol suppose to help me?

Answer 27

OpenStudy is not for direct answers. OpenStudy is to help you learn. You said you didn't understand it and it is due tomorrow. And then next week when you have a test over it? What are you going to do then? See if we give you the answer you will ask a similar problem again. But if we explain it to you and teach you it then you can solve the similar problems and will be able to pass your test!

Answer 28

And also @Clalgee @acxbox22 good job for not giving a direct answer! Keep up the good work! And also btw they are going on the correct path with your question. So do what they say and you will learn in no time! And understand how to solve it.

Answer 29

Then why do so much other people get answers? Alright fine, I need help but I need help fast... @Clalgee and @acxbox22 don't make sense.

Answer 30

First do this and tell us what you get.

\(\color{blue}{\text{Originally Posted by}}\) @acxbox22
first use pythagorean theorum to find the hypotenuse
\(\color{blue}{\text{End of Quote}}\)

Answer 31

^^^
ya know we all dont say the same thing for no reason
continuing, find the hypotenuse using pythagorean theorum
12^2+20^2=x^2
544=x^2
x=sqrt544
sqrt544 is the hypotenuse

Answer 32

Lets stop lecturing the poor guy and HELP HIM. That's what this site is for. Don't become too full of yourselves and lose sight of that. Ty @acxbox22

Answer 33

lol

Answer 34

there i got you started
now we have hypotenuse and adjacent
so we can plug them in cos(theta)=adjacent/hypotenuse

Answer 35

If we want to help him we need cooperation from him.

Answer 36

@Christine88

Answer 37

@Christine88 What is RQ equal to? Look at the graph and tell us. @acxbox22 helped you find the hypotenuse. Now it's your tun to fin the adjacent.

Answer 38

I'm a her and no one is making sense. Everyone is telling me two and three different things. I don't understand.

Answer 39

well we all told you to first get the hypotennuse.

Answer 40

Alright. The adjacent angle is 12 cause that what the graph says. Now what

Answer 41

@Christine88 Now write the equation. It use to be RQ/PR. Now what is it?

Answer 42

No @TheSmartOne the first thing you said was lol like that was going to help me

Answer 43

@Christine88 Please stop. If you want to finish solving this equation, you need to focus on the equation.

Answer 44

We are all trying to help you. We just need your cooperation and patience.

Answer 45

Yeah but @thesmartone kept saying lol. Lol is not going to help.

Answer 46

The equation use to be RQ/PR. Now what is it?

Answer 47

Why are you all ignoring me/

Answer 48

ok i am back
cos(theta)=adjacent/hypotenuse
cos(theta)=12/(sqrt544)
we plugged in our values now we can put it into a calculator and solve

Answer 49

That doesn't make any sense

Answer 50

You have to divide 12 by square root 544.

What is your answer?

Answer 51

why? we plugged in our known values for the adjacent and hypotenuse sides
we already said adjacent side was 12 and the hypotenuse was sqrt544
now using the ration for cosine we can plug it in and solve

Answer 52

oh. 0.514?

Answer 53

yes!good job!

Answer 54

Yes! That is the correct answer! Do you see how easy that was?

Answer 55

Nice work! @acxbox22

Answer 56

see we can work together to help you get an answer and learn the material!

Answer 57

That wasn't even easy. There was a lot of people and everyone was saying so many different things.

Answer 58

i understand, but it becomes easier for everyone else to help if the user cooperates

Answer 59

I'm sorry you had trouble, but you shouldn't have tagged so many people if you knew if was going to be a bother. Anyways, you finished the equation! great work :)

Answer 60

Do you see what @clalgee said?? I'm sorry but you can't tell me what to do you are not my boss and you didn't even help me. You ignored me and you criticize me. @acxbox22 is the only person that helped me.

Answer 61

@Clalgee helped you understand the basics and i carried on from there
now lets finish on a happy note ;)

Answer 62

Thank you @acxbox22 we worked together and we solved the problem! Good job to everyone!

Answer 63

No! @Clalgee @ShadowLegendX @thesmartone didn't do anything. I'm sorry but I have to say it. And clalgee is ignoring me again

Answer 64

Thanks for nothing. Bye.


Thank you @acxbox22 for helping me.

Answer 65

Bye! Have a nice day! :)

Answer 66

Matter of fact I only said "lol" once. And that too because it was funny how you wanted direct answers.

Answer 67

And also when multiple people are helping you get confused, so I left. I knew you were in good hands with @acxbox22