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Mathematics 16 Online
OpenStudy (anonymous):

will fan for help

OpenStudy (anonymous):

Solve for the variable. 3/9=p/24 A. 1/8 B. 1/3 C. 3 D. 8

OpenStudy (solomonzelman):

simplify on the left side, and then multiply both sides times 24. OR, multiply both sides times 24, and then simplify the left side

OpenStudy (anonymous):

i cannot figure it out i am stuck

OpenStudy (solomonzelman):

\(\large\color{black}{ \frac{\LARGE 3 }{\LARGE9}=\frac{\LARGE p }{\LARGE 24} }\) can you simplify the left side?

OpenStudy (solomonzelman):

(Hint: both 9 and 3 are divisible by 3)

OpenStudy (solomonzelman):

\(\large\color{black}{ \frac{\LARGE 3 \color{red}{\div3} }{\LARGE9 \color{red}{\div3}}=\frac{\LARGE p }{\LARGE 24} }\)

OpenStudy (solomonzelman):

re-write it for me please (dividing the top and bottom as I said in red)

OpenStudy (anonymous):

3/3=1 and 9/3=3

OpenStudy (solomonzelman):

yes, so what will your left side look like?

OpenStudy (anonymous):

1/3=p/24

OpenStudy (solomonzelman):

yes it will be \(\large\color{black}{ \frac{\LARGE 1 }{\LARGE 3}=\frac{\LARGE p }{\LARGE 24} }\)

OpenStudy (solomonzelman):

Now, \(\large\color{black}{ \frac{\LARGE 1\color{blue}{\times 8} }{\LARGE 3\color{blue}{\times 8}}=\frac{\LARGE p }{\LARGE 24} }\)

OpenStudy (solomonzelman):

what it will then be?

OpenStudy (anonymous):

8/24

OpenStudy (solomonzelman):

\(\large\color{black}{ \frac{\LARGE 8 }{\LARGE 24}=\frac{\LARGE p }{\LARGE 24} }\)

OpenStudy (solomonzelman):

So what can you say about \(\large\color{black}{ p }\) ?

OpenStudy (solomonzelman):

Hint: If you are given that: \(\large\color{black}{ \frac{\LARGE c }{\LARGE b}=\frac{\LARGE a }{\LARGE b} }\) then you can conclude that: \(\large\color{black}{c=a }\)

OpenStudy (solomonzelman):

you are given that: \(\large\color{black}{ \frac{\LARGE 8 }{\LARGE 24}=\frac{\LARGE p }{\LARGE 24} }\) \(\large\color{black}{.... }\) can you finish it ?

OpenStudy (anonymous):

would it be d because that is the one that would make it =

OpenStudy (solomonzelman):

yes, it is D.

OpenStudy (anonymous):

thanks @SolomonZelman

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